I’m pretty sure this is correct.

Okay, I am not the big mathematician that can give you the actual equations but even though 1 in 292.2 million is the single number combination ticket chances of winning, 10 different number combination tickets does not work out to 1 in 29.22 million. However the odds do not stay at 1 in 292.2 million like mention and do get better. It is just not that drastic as each ticket has its own odds against the numbers that are left.
Assuming each ticket has unique numbers:
1 ticket = 1 in 292.2 combinations
2 tickets = 1 in (292.2 million minus the first ticket combination)
3 tickets = 1 in (292.2 million minus the first 2 ticket combinations)
4 tickets = 1 in (292.2 million minus the first 3 tickets combinations)
and so on.

It is a combinatorial probability problem and I’ll leave it to someone with a mathematician in the family to find out what 10 tickets out of 292.2 million works out to as far as odds are. However once all 292.2 million combinations are bought, the probability of winning is like 1 in 1 for that last ticket or something like that. Any statisticians out there?