Ranger 620 Owners Question

Will be picking up a 2013 Ranger 620 with 250 verado. My question is if I have a 21 x 21 garage will it fit if i angle the boat and turn the verado to one side?

Well I highly doubt it even with a swing tongue. I had a pro v 1900 with a swing tongue and it barely fit in my 28×30 garage.

woody-1961 wrote:

Well I highly doubt it even with a swing tongue. I had a pro v 1900 with a swing tongue and it barely fit in my 28×30 garage.

I had an 08 619 that fit before no problem in the same garage and i know they are long and wider then your 1900. How does your lund barely fit a 28ft garage….. Lunds trailer must be that much longer then a Ranger.

I have a 692vs that’s 18’10” and I can’t fit it in my 20×20, not even close.

Total package length for yours is 25 ft. 1 in. with motor down

Joel VandeKrol wrote:

I have a 692vs that’s 18’10” and I can’t fit it in my 20×20, not even close.

Total package length for yours is 25 ft. 1 in. with motor down

Correct me if i’m wrong but the 692 doesn’t have a swing away tongue.

My 1998 Ranger 690 didnt, that bought was long on the trailer then my 08 619

Joel is right and if you have a swing tongue it is 23 feet 1 inch. If you figure the diagonal on a 21 by 21 foot garage you will get about 29.5 feet. There should be enough room at that angle, but moving a 620 ranger by hand on a double axle trailer in nearly impossible. You will have to use almost the entire garage for it to fit.

candofish wrote:

Joel is right and if you have a swing tongue it is 23 feet 1 inch. If you figure the diagonal on a 21 by 21 foot garage you will get about 29.5 feet. There should be enough room at that angle, but moving a 620 ranger by hand on a double axle trailer in nearly impossible. You will have to use almost the entire garage for it to fit.

This might be a dumb question buy how did you come up with 29.5 ft?

bradl110 wrote:

<div class=”d4p-bbt-quote-title”>candofish wrote:</div>
Joel is right and if you have a swing tongue it is 23 feet 1 inch. If you figure the diagonal on a 21 by 21 foot garage you will get about 29.5 feet. There should be enough room at that angle, but moving a 620 ranger by hand on a double axle trailer in nearly impossible. You will have to use almost the entire garage for it to fit.

This might be a dumb question buy how did you come up with 29.5 ft?

Pythagorean theorem I’m guessing

a squared + b squared = c squared

The problem you will have is with such a wide beam, you’ll be 3-4′ out from the corner that measured 29.5′.

Get a board and cut it the length of the beam, lay it in the corner at an angle and measure perpendicular from the board. That should get you close

Good Luck

Attachments:

1. 

   Capture.png
   

I used the theorem. The motor will fit in the angle towards the back of the garage. The boat width would be about 8 feet. If you back the boat in at a 45 degree angle till it almost touches the walls, it would use up about 6 feet on each wall. From the back of the boat to the front of the trailer, with a swing tongue would be about 21 feet, because the motor is in the angle of the 2 walls. So using the theorem again. 6 feet squared equals 36 plus 1/2 the 8 foot of the boat would be 4 feet squared equals 16 or 36+16= 52 The square root would be about 7 feet. So 7 feet from the wall and add 21 for the boat and trailer would be 28 feet total in length. It would fit, but again moving a 3000 LB boat and trailer by hand would be hard.

Pete S wrote:

<div class=”d4p-bbt-quote-title”>bradl110 wrote:</div>

<div class=”d4p-bbt-quote-title”>candofish wrote:</div>
Joel is right and if you have a swing tongue it is 23 feet 1 inch. If you figure the diagonal on a 21 by 21 foot garage you will get about 29.5 feet. There should be enough room at that angle, but moving a 620 ranger by hand on a double axle trailer in nearly impossible. You will have to use almost the entire garage for it to fit.

This might be a dumb question buy how did you come up with 29.5 ft?

Pythagorean theorem I’m guessing

a squared + b squared = c squared

The problem you will have is with such a wide beam, you’ll be 3-4′ out from the corner that measured 29.5′.

Get a board and cut it the length of the beam, lay it in the corner at an angle and measure perpendicular from the board. That should get you close

Guess I should have paid more attention in Math class……

The diagram by Mookie is great. It is easier to understand then what I typed.

Attachments:

1. 

   dumb-and-dummer.jpg
   

If you figure it out, I would suggest painting the rear pivot point onto the floor as well as the tongue swing.

Mookie Blaylock wrote:

If you figure it out, I would suggest painting the rear pivot point onto the floor as well as the tongue swing.

good idea.

Put a mark from the back wall, 8′-1 1/2″ towards the front.
And from the right wall, 2′-10″ towards the left.

You may be able to squeak it in with about an inch to spare.
Maybe not.

If you do make it you will use every inch of space and require some precision and strength just to position it. An 18′ Lund with the breakaway tongue has to be angled in my garage that’s 24′ deep with a small workbench across the front. I’ve tried moving aluminum boats with dual axles that weigh considerably less and it’s nearly impossible.

In your position, I’d assume it will not fit (or be worth the hassle)…and plan accordingly.

I was wrong on the weight of the boat. My 2011 Ranger 620 fully loaded weighs in at 5950 Lbs. I weighed it last summer on a scale. I have an etec 250, an etec 15 kicker, and a talon on the back.

Mookie Blaylock wrote:

Good Luck

show off